Freedom Town: Aesthetic and Recreational Lawn Alternative
- Thread starter BASEDVATO
- Start date
I'm just joking.
I actually imagine more of a Nic Cage in Leaving Las Vegas without the personality or the sexy prostitute.
Take care of yourself buddy.
I actually imagine more of a Nic Cage in Leaving Las Vegas without the personality or the sexy prostitute.
Take care of yourself buddy.
Props:
infinity
f(x)=3(x-5)²+7
=(3(x-5)(x-5))+7
=(3(x²-10x+25))+7
=(3x²-30x+75)+7
=3x²-30x+82
3x²-30x+82=0
x=-30+/-((-30)²-4(3*82))^1/2)/2(3)
x=5+i(7/3)^1/2, x=5-i(7/3)^1/2
A one-to-one function is a function in which each output value corresponds to exactly one input value. This is a quadratic function and a parabola. Its graph can be intersected with a horizontal line and the same output can be found at reflected positive and negative input values. Therefore it cannot be a one-to-one function.
=(3(x-5)(x-5))+7
=(3(x²-10x+25))+7
=(3x²-30x+75)+7
=3x²-30x+82
3x²-30x+82=0
x=-30+/-((-30)²-4(3*82))^1/2)/2(3)
x=5+i(7/3)^1/2, x=5-i(7/3)^1/2
A one-to-one function is a function in which each output value corresponds to exactly one input value. This is a quadratic function and a parabola. Its graph can be intersected with a horizontal line and the same output can be found at reflected positive and negative input values. Therefore it cannot be a one-to-one function.
Props:
infinity
